| Author | [HWM Daily] Griffin’s Cup FFA Tournament |
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Dear Lords,
The official newspaper HWM Daily and HWM Radio declare the beginning of double elimination tournament “Griffin’s Cup” held between different MCs!
http://daily.heroeswm.ru/newscom.php?i=ffa-tournament-griffins-cup |
| nice reward mostly cover the art expense for winner and 2nd :P |
I wanna see A&D particiapate :)
They do have some pretty skilled chaps :D |
L_E_S_E_N_A, ever considered renaming your English branch as LWM daily? xP
I am making a blind guess here, but is Angel sponsoring those 500 diamonds? :p |
L_E_S_E_N_A, ever considered renaming your English branch as LWM daily? xP
oh, it doesn't matter :)
moreover, it's too difficult to find a person who can change the web code in Daily xD
I am making a blind guess here, but is Angel sponsoring those 500 diamonds? :p
no, Empire is a sponsor :) |
For higher levels :/
really wanted to participate :( |
Damn 500 diamonds, would same me so much gold for UCI, but I hate PvP.
Good luck to participants ! |
Damn 500 diamonds, would same me so much gold for UCI, but I hate PvP.
The prize fund 500 diamonds etc.. reward will be divided amongst all the members of the MC. Its not for one individual.
(as far as I understand it) |
| The prize fund 500 diamonds etc.. reward will be divided amongst all the PARTICIPANTS of the MC |
| Hmmm, yeah but probably only for the participants of the MC. |
too bad, .com members and MC's are no match :(
GL for those who are trying. |
yeah :(
But,
Is there any minimum number of member applications required in order for the MC to qualify? (for entering this tournament)
or just one member can participate? |
| 1.3 Main characters, members of MC-participants can take part in the tournament. They must enter the MC at least 3 hours before the battle starts. One character must be a member of only 1 MC-participant. |
Eddy, i don't see how that answers ajith's question.
1.3 states that a participant can belong to only one MC. |
| If the number of applicants is not divisible by 8, the number of chosen participants will be rounded down to the number divisible by 8. |
| closed by l_e_s_e_n_a (2014-11-19 11:03:33) |
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