| Author | Maths Problems |
|---|
Nope the question is to arrange them in the order of decreasing(or increasing) magnitude.
That question requires high order thinking skills(HOTS), is of 10 marks and time is 3 mins.
It was in some maths olympiad. :)
You cant use a calculator and if you try solving that on paper then atleast 15 mins are required. :P |
| the person who solves that must have a really good IQ :) |
It does not require any special IQ. Just a basic understanding of the calculations involved. I didn't take time, but it took significantly less than a minute to sort them. I did spend some time with them when I wrote my previous answer so I had a head start, but a question like that should never take a full minute to solve.
1) 22222
2) 2222^2
4) 2^2^2^22
3) 22^22^2
5) 2^2^222
However, the question in post 19 by Majblomma was very interesting indeed. I dare say that it requires some IQ to solve. It was the first time I encountered that kind of inductive puzzle. Thanks a lot for that one. |
Actually the correct increasing order is 1,2,3,4,5
:)
But it seems u got the problem and I agree its basic but it requires a good understanding of numbers :)
Anyways a cookie for you :P :D |
Larry and Gary are playing Golf. If Larry gives 6 of his clubs to Gary, then they will have the same amount of clubs. If Garry gives 6 of his clubs to Larry, then Larry will have 3 times a many clubs as Gary.
How many clubs does Larry have, and how many does Gary have? |
| [Post deleted by moderator ElfPride // As requested by author] |
| 46 hurts my eyes, remove it please |
| [Post deleted by moderator ElfPride // As requested by author] |
| closer, but still not correct... |
| wrong again. please, remove 46 and 48 |
A: L - 6 = G + 6
B: L + 6 = 3 * (G - 6)
B - A gives us
12 = 3G - 18 - G - 6
36 = 2G
G = 18
L = 30 |
Larry and Gary are playing Golf. If Larry gives 6 of his clubs to Gary, then they will have the same amount of clubs. If Garry gives 6 of his clubs to Larry, then Larry will have 3 times a many clubs as Gary.
How many clubs does Larry have, and how many does Gary have?
x=larry & y=garry
a) x-6=y+6
b) x+6=(y-6)*3
b-a) 12=3y-18-y-6=>2y-24=12
y=18
x=30 |
| lol I didn't see that correct answer has already been posted by Majblomma |
38 -
Let us take those 12 swords in groups of 4. So we have 3 groups.
Now take any two groups and measure them on the scale. = 1 measure.
If it is unbalanced, then take one of them and the one kept aside and measure them. If they're balanced, then the group not measured in this one has the fake sword. = 2 measures.
Now take the swords of these 4 in pairs and measure them. = 3 measures.
There will be an imbalance. Take any one pair and measure its 2 swords. If it is balanced, then the fake sword is in the other pair. = 4 measures.
Now take the pair with the fake sword and measure the two swords. One will be lighter than the other. = 5 measures.
Take the lighter sword and measure it with any other sword. = 6 measures.
If there is an imbalance, then the lighter one was the fake sword. If not, then the heavier one was the fake sword. |
45 -
Let the no. of clubs with Gary be G and with Lary be L.
ATQ,
>>L - 6 = G + 6
>>L + 6 = 3(G - 6)
Solving, we get,
12 = 2G - 24
So, G = 18 and L = 30 |
Post 45, gt4dom:
Larry and Gary are playing Golf. If Larry gives 6 of his clubs to Gary, then they will have the same amount of clubs. If Garry gives 6 of his clubs to Larry, then Larry will have 3 times a many clubs as Gary.
I first thought this was a very simple equation system and that the answer was so obvious so I didn’t even bother. Later, I noticed that it got a hidden trick that suddenly made it slightly more interesting.
1: L - 6 = G + 6 --> G = L - 12
2: L + 6 = 3G
Substitute G: L + 6 = 3(L - 12)
Result:
Larry got 21 clubs
Gary got 9 clubs
Post 54, narutoayan:
A very good try, but I'm not ready to part with that much gold. Please find a better way.
It might help if you make a better structure by branching it. After the first measurement you will have 3 cases. Right heavier, Left heavier and Equal. For each case you describe the measurements you intend to do. Proceed like that that, generating 3 times more cases each measurement. In your final answer, you may simplify it and clump together the obvious cases.
This is indeed a difficult problem. At the same time, you don't need any education or special skill to solve it. |
for Lord STB:
check your second eqn..
you are assuming that this
then Larry will have 3 times a many clubs as Gary.
mentions the clubs Gary already have..but it means the the clubs gary will be left with ...
if it wasn't so ..how did u write eqn 1 correct? |
Post 45, gt4dom:
Larry and Gary are playing Golf. If Larry gives 6 of his clubs to Gary, then they will have the same amount of clubs. If Garry gives 6 of his clubs to Larry, then Larry will have 3 times a many clubs as Gary.
I first thought this was a very simple equation system and that the answer was so obvious so I didn’t even bother. Later, I noticed that it got a hidden trick that suddenly made it slightly more interesting.
1: L - 6 = G + 6 --> G = L - 12
2: L + 6 = 3G
Substitute G: L + 6 = 3(L - 12)
Result:
Larry got 21 clubs
Gary got 9 clubs
Here L + 6 will be equal to 3(G - 6), isn't it?
And okay, I'll try that question again, thanks :) |
if it wasn't so ..how did u write eqn 1 correct?
Here L + 6 will be equal to 3(G - 6), isn't it?
Interesting questions indeed. So why did I not write it exactly as the previous seemingly correct answers? (You will think I'm really silly. :) |
Larry got 21 clubs
Gary got 9 clubs ????
Did you verify your result before posting |
